l2345679x81の日記

l2345679x81の日記

Python

newton

√x r(0) = x r(n) = (r(n-1)^2 + x) / 2r(n-1) √7 r(0) = 7 r(1) = (7*7 + 7) / (2*7) = 4 r(2) = (4*4 + 7) / (2*4) = 2.875 r(3) = (2.875*2.875 + 7) / (2*2.875) = 2.654891304 r(4) = (2.654891304*2.654891304 + 7) / (2*2.654891304) = 2.645767044 r…